leetcode-daily/cpp/2205/220509-CN.cpp

36 lines
882 B
C++

#include <vector>
#include <string>
#include <iostream>
/**
* 942. DI String MatchA permutation perm of n + 1 integers of all the integers in the range [0, n] can be represented as a string s of length n where:
*
* s[i] == 'I' if perm[i] < perm[i + 1], and
* s[i] == 'D' if perm[i] > perm[i + 1].
* Given a string s, reconstruct the permutation perm and return it. If there are multiple valid permutations perm, return any of them.
*
*/
class Solution {
public:
static std::vector<int> diStringMatch(const std::string& s) {
int p = 1, n = -1;
std::vector<int> ret;
ret.reserve(s.length() + 1);
ret.push_back(0);
for (char c : s)
ret.push_back(c == 'I' ? p++ : n--);
n = (-n) - 1;
for (int& i : ret)
i += n;
return ret;
}
};
int main() {
auto r = Solution::diStringMatch("DDI");
for (const auto& i : r)
std::cout << i << ' ';
return 0;
}