leetcode-daily/cpp/2302/230219.cpp

46 lines
1.1 KiB
C++

#include <vector>
#include <utility>
#include <queue>
#include <algorithm>
struct TreeNode {
int val;
TreeNode* left;
TreeNode* right;
explicit TreeNode(int x, TreeNode* left = nullptr, TreeNode* right = nullptr) : val(x), left(left), right(right) {}
};
/**
* 103. Binary Tree Zigzag Level Order Traversal
*
* Given the root of a binary tree, return the zigzag level order traversal of its nodes' values. (i.e., from left to right, then right to left for the next level and alternate between).
*/
class Solution {
public:
static std::vector<std::vector<int>> zigzagLevelOrder(const TreeNode* root) {
if (!root)
return {};
std::vector<std::vector<int>> ret {{}};
std::queue<std::pair<const TreeNode*, int>> q;
q.emplace(root, 0);
for (int n = 0; !q.empty(); ) {
const auto [ptr, lv] = q.front();
q.pop();
if (lv > n) {
ret.emplace_back();
++n;
}
ret.back().push_back(ptr->val);
if (ptr->left)
q.emplace(ptr->left, 1 + lv);
if (ptr->right)
q.emplace(ptr->right, 1 + lv);
}
for (int i = 1; i < ret.size(); i += 2)
std::reverse(ret[i].begin(), ret[i].end());
return ret;
}
};