leetcode-daily/cpp/2206/220609.cpp

24 lines
1.0 KiB
C++

#include <vector>
#include <algorithm>
/**
* 167. Two Sum II - Input Array Is Sorted
* Given a 1-indexed array of integers numbers that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target number. Let these two numbers be numbers[index1] and numbers[index2] where 1 <= index1 < index2 <= numbers.length.
* Return the indices of the two numbers, index1 and index2, added by one as an integer array [index1, index2] of length 2.
* The tests are generated such that there is exactly one solution. You may not use the same element twice.
* Your solution must use only constant extra space.
*/
class Solution {
public:
std::vector<int> twoSum(const std::vector<int>& numbers, int target) {
for (int i = 0; numbers[i] <= target - numbers[i]; ++i) {
int pos = std::lower_bound(numbers.begin() + i + 1, numbers.end(), target - numbers[i]) - numbers.begin();
if (pos == numbers.size() || numbers[pos] + numbers[i] != target)
continue;
return {i + 1, pos + 1};
}
return {};
}
};