33 lines
1.2 KiB
C++
33 lines
1.2 KiB
C++
#include <string>
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#include <iostream>
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/**
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* 1021. Remove Outermost Parentheses
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* A valid parentheses string is either empty "", "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation.
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* For example, "", "()", "(())()", and "(()(()))" are all valid parentheses strings.
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* A valid parentheses string s is primitive if it is nonempty, and there does not exist a way to split it into s = A + B, with A and B nonempty valid parentheses strings.
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* Given a valid parentheses string s, consider its primitive decomposition: s = P1 + P2 + ... + Pk, where Pi are primitive valid parentheses strings.
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* Return s after removing the outermost parentheses of every primitive string in the primitive decomposition of s.
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*/
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class Solution {
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public:
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static std::string removeOuterParentheses(const std::string& s) {
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int stack = 0, prev = 0;
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std::string ans;
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const int n = s.length();
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for (int i = 0; i < n; ++i) {
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if (0 == (s[i] == '(' ? ++stack : --stack)) {
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ans += s.substr(prev + 1, i - prev - 1);
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prev = i + 1;
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}
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}
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return ans;
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}
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};
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int main() {
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std::cout << Solution::removeOuterParentheses("()()");
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return 0;
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}
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