leetcode-daily/cpp/2206/220612.cpp

53 lines
1.4 KiB
C++

#include <vector>
#include <unordered_set>
#include <cstdio>
/**
* 1695. Maximum Erasure Value
* You are given an array of positive integers nums and want to erase a subarray containing unique elements. The score you get by erasing the subarray is equal to the sum of its elements.
* Return the maximum score you can get by erasing exactly one subarray.
* An array b is called to be a subarray of a if it forms a contiguous subsequence of a, that is, if it is equal to a[l],a[l+1],...,a[r] for some (l,r).
*/
class Solution {
public:
static int maximumUniqueSubarray(const std::vector<int>& nums) {
std::unordered_set<int> s;
const int n = nums.size();
int sum = 0, ret = 0;
for (int i = 0, l = 0; i < n; ++i) {
std::printf("In loop, i = %d, l = %d\nStart inserting: ", i, l);
for (; i < n && !s.count(nums[i]); ++i) {
sum += nums[i];
s.insert(nums[i]);
std::printf("%d ", nums[i]);
}
ret = std::max(ret, sum);
if (i == n)
break;
std::printf("\nEnd inserting at position %d, nums[i] = %d, updating ret <- %d\nStart popping: ", i, nums[i], ret);
// pop until reach nums[i]
for (; nums[l] != nums[i]; ++l) {
s.erase(nums[l]);
sum -= nums[l];
std::printf("%d ", nums[l]);
}
++l; // where nums[l] == nums[i]
std::printf("\nEnd loop, where i = %d, l = %d\n\n", i, l);
}
return ret;
}
};
int main() {
std::printf("%d\n", Solution::maximumUniqueSubarray({
187
}));
return 0;
}