leetcode-daily/2201/220123.cpp

51 lines
1.3 KiB
C++

#include <vector>
#include <cstdio>
template<int L, int R>
struct TableGenerator {
int answer[50] {};
int size = 0;
constexpr TableGenerator() : answer(), size(0) {
auto gen = [](int begin, int digits) {
int ret = begin;
for (int i = 1; i < digits; ++i) {
ret = 10 * ret + (i + begin);
}
return ret;
};
int digitsL = 0, beginL, ans = 0;
for (int i = L; i; i /= 10) {
++digitsL;
beginL = i;
}
for (int d = digitsL, lim = std::min(R, 123456789); ans < lim; ++d) {
for (int b = (d == digitsL) ? beginL : 1; ans < lim && b + d <= 10; ++b) {
answer[size++] = ans = gen(b, d);
}
}
}
};
/**
* 1291. Sequential Digits
* An integer has sequential digits if and only if each digit in the number is one more than the previous digit.
* Return a sorted list of all the integers in the range [low, high] inclusive that have sequential digits.
*/
class Solution {
private:
inline static constexpr TableGenerator<10, 1000000000> table;
public:
static std::vector<int> sequentialDigits(int low, int high) {
return {std::lower_bound(table.answer, table.answer + table.size, low), std::lower_bound(table.answer, table.answer + table.size, 1 + high)};
}
};
int main() {
auto ret = Solution::sequentialDigits(1000, 123456789);
for (int i : ret)
std::printf("%d\n", i);
return 0;
}