leetcode-daily/cpp/2203/220310.cpp

42 lines
1.1 KiB
C++

#include <iostream>
/**
* Definition for singly-linked list.
*/
struct ListNode {
int val;
ListNode* next;
explicit ListNode(int x = 0, ListNode* next = nullptr) : val(x), next(next) {}
};
/**
* 2. Add Two Numbers
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
* You may assume the two numbers do not contain any leading zero, except the number 0 itself.
*/
class Solution {
public:
static ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
if (!l1 || !l2)
return l1 ? l1 : l2;
int cin = (l1->val + l2->val) / 10;
ListNode* ret = new ListNode((l1->val + l2->val) % 10);
ListNode* ptr = ret;
for (ListNode* ptr1 = l1->next, * ptr2 = l2->next; ptr1 || ptr2; ) {
int cur = cin + (ptr1 ? l1->val : 0) + (ptr2 ? l2->val : 0);
ptr = ptr->next = new ListNode(cur % 10, nullptr);
cin = cur / 10;
ptr1 = ptr1 ? ptr1->next : nullptr;
ptr2 = ptr2 ? ptr2->next : nullptr;
}
if (cin)
ptr->next = new ListNode(cin, nullptr);
return ret;
}
};