leetcode-daily/cpp/2204/220419.cpp

51 lines
1.1 KiB
C++

#include <functional>
#include <cstdio>
struct TreeNode {
int val;
TreeNode* left;
TreeNode* right;
explicit TreeNode(int x = 0, TreeNode* l = nullptr, TreeNode* r = nullptr) : val(x), left(l), right(r) {}
};
/**
* 99. Recover Binary Search Tree
* You are given the root of a binary search tree (BST), where the values of exactly two nodes of the tree were swapped by mistake. Recover the tree without changing its structure.
*/
class Solution {
public:
static void recoverTree(TreeNode* root) {
TreeNode* prev = nullptr, * x1 = nullptr, * x2 = nullptr;
std::function<bool(TreeNode*)> traverse = [&](TreeNode* r) {
if (!r)
return false;
if (r->left && traverse(r->left))
return true;
// Check if prevPrev < r
if (prev && prev->val >= r->val) {
x1 = r;
if (!x2)
x2 = prev;
else
return true;
}
prev = r;
if (r->right)
return traverse(r->right);
return false;
};
traverse(root);
std::swap(x1->val, x2->val);
}
};
int main() {
auto* root = new TreeNode(1, new TreeNode(3, nullptr, new TreeNode(2)));
Solution::recoverTree(root);
return 0;
}