leetcode-daily/cpp/2204/220407.cpp

38 lines
1.1 KiB
C++

#include <vector>
#include <queue>
#include <iostream>
/**
* 1046. Last Stone Weight
* You are given an array of integers stones where stones[i] is the weight of the ith stone.
*
* We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x and y with x <= y. The result of this smash is:
*
* If x == y, both stones are destroyed, and
* If x != y, the stone of weight x is destroyed, and the stone of weight y has new weight y - x.
* At the end of the game, there is at most one stone left.
*
* Return the smallest possible weight of the left stone. If there are no stones left, return 0.
*/
class Solution {
public:
static int lastStoneWeight(const std::vector<int>& stones) {
std::priority_queue<int> q(stones.begin(), stones.end());
while (q.size() > 1) {
int x = q.top();
q.pop();
x = std::abs(q.top() - x);
q.pop();
if (x)
q.push(x);
}
return q.empty() ? 0 : q.top();
}
};
int main() {
std::cout << Solution::lastStoneWeight({1, 3});
return 0;
}