#include #include /** * #1185. Day of the Week * Given a date, return the corresponding day of the week for that date. * The input is given as three integers representing the day, month and year respectively. * Return the answer as one of the following values {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}. * * Input: day = 18, month = 7, year = 1999 * Output: "Sunday" * * Range: year <- [1971, 2100] */ class Solution { private: inline static const std::string weekName[7] = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" }; inline static const int monthDays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334}; public: static std::string dayOfTheWeek(int day, int month, int year) { // Starts at 1969-01-01 [Wednesday] // (365 * 4 + 1) % 7 == 5, 365 % 7 == 1 // 1969, +1 ~ +3 will not experience leap years. return weekName[(3 + (((year - 1969) >> 2) * 5) + ((year - 1969) & 3) + monthDays[month - 1] + day - 1 + (((year - 1969) & 3) == 3 && month > 2 && year != 2100 ? 1 : 0)) % 7]; } }; int main() { int n[12] {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; int ans, prev = 4; for (int y = 1971; y <= 2100; ++y) { for (int m = 1; m <= 12; ++m) { for (int d = 1; d <= ((!(y & 3) && m == 2 && y != 2100) ? 29 : n[m - 1]); ++d) { if ((ans = /* Solution::dayOfTheWeek(d, m, y) int when debug */ 0) != (prev = (prev + 1) % 7)) { std::printf("%d-%02d-%02d -> %d != %d\n", y, m, d, ans, prev); std::printf("ILLEGAL!\n"); return 1; } } } } return 0; }