add: 220109-CN

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Lam Haoyin 2022-01-09 00:43:51 +08:00
parent 0161961c32
commit ed1fa6be61
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2 changed files with 35 additions and 1 deletions

34
2201/220109-CN.cpp Normal file
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#include <vector>
#include <string>
/**
* 1629. Slowest Key
* A newly designed keypad was tested, where a tester pressed a sequence of n keys, one at a time.
* You are given a string keysPressed of length n, where keysPressed[i] was the ith key pressed in the testing sequence, and a sorted list releaseTimes, where releaseTimes[i] was the time the ith key was released. Both arrays are 0-indexed. The 0th key was pressed at the time 0, and every subsequent key was pressed at the exact time the previous key was released.
* The tester wants to know the key of the keypress that had the longest duration. The ith keypress had a duration of releaseTimes[i] - releaseTimes[i - 1], and the 0th keypress had a duration of releaseTimes[0].
* Note that the same key could have been pressed multiple times during the test, and these multiple presses of the same key may not have had the same duration.
* Return the key of the keypress that had the longest duration. If there are multiple such keypresses, return the lexicographically largest key of the keypresses.
*/
class Solution {
public:
static char slowestKey(const std::vector<int>& releaseTimes, const std::string& keysPressed) {
int len = keysPressed.length(), max = 0, prev = 0;
char ret = 0;
for (int i = 0; i < len; ++i) {
if (releaseTimes[i] - prev > max) {
max = releaseTimes[i] - prev;
ret = keysPressed[i];
} else if (releaseTimes[i] - prev == max) {
ret = std::max(ret, keysPressed[i]);
}
prev = releaseTimes[i];
}
return ret;
}
};
int main() {
std::printf("%c\n", Solution::slowestKey({9, 29, 49, 50}, "cbcd"));
return 0;
}

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@ -3,4 +3,4 @@ PROJECT(2201)
SET(CMAKE_CXX_STANDARD 23) SET(CMAKE_CXX_STANDARD 23)
ADD_EXECUTABLE(2201 220108.cpp) ADD_EXECUTABLE(2201 220109-CN.cpp)