add: 220505 [cpp]

cpp/2205/220506.cpp

@@ -0,0 +1,149 @@
+#include <string>
+#include <vector>
+#include <chrono>
+#include <iostream>
+
+template<typename T>
+struct ListNode {
+	T data;
+	ListNode<T>* prev;
+	ListNode<T>* next;
+
+	explicit ListNode(T d, ListNode<T>* p = nullptr, ListNode<T>* n = nullptr) : data(std::move(d)), prev(p), next(n) {}
+	ListNode(ListNode<T>* p, ListNode<T>* n) : prev(p), next(n) {}
+};
+
+template<typename T>
+struct LinkedList {
+	unsigned long long size = 0;
+	ListNode<T>* front = nullptr;
+	ListNode<T>* rear = nullptr;
+
+	LinkedList() {
+		front = new ListNode((ListNode<T>*)nullptr, (ListNode<T>*)nullptr);
+		rear = new ListNode(front, (ListNode<T>*) nullptr);
+		front->next = rear;
+	}
+
+	void push_back(T data) {
+		auto* node = new ListNode(data, rear->prev, rear);
+		rear->prev = rear->prev->next = node;
+		++size;
+	}
+
+	ListNode<T>* erase(ListNode<T>* node) {
+		auto ret = node->next;
+		node->prev->next = node->next;
+		node->next->prev = node->prev;
+		delete node;
+		--size;
+		return ret;
+	}
+
+	bool empty() const {
+		return !size;
+	}
+
+	ListNode<T>* begin() {
+		return front->next;
+	}
+
+	ListNode<T>* end() {
+		return rear;
+	}
+};
+
+/**
+ * 1209. Remove All Adjacent Duplicates in String II
+ * You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and the right side of the deleted substring to concatenate together.
+ * We repeatedly make k duplicate removals on s until we no longer can.
+ * Return the final string after all such duplicate removals have been made. It is guaranteed that the answer is unique.
+ */
+
+class Solution {
+public:
+	static std::string removeDuplicates(const std::string& s, int k) {
+		if (s.empty())
+			return {};
+
+		LinkedList<std::pair<char, int>> cnt;
+		{
+			int c = 1;
+			char current = *s.c_str();
+			for (const char* ptr = s.c_str() + 1; *ptr; ++ptr) {
+				if (*ptr == current) {
+					++c;
+					continue;
+				}
+				cnt.push_back({current, c});
+				c = 1;
+				current = *ptr;
+			}
+			cnt.push_back({current, c});
+		}
+
+		// Remove & Merge
+		for (auto ptr = cnt.begin(); ptr != cnt.end();) {
+			// Now, nothing can be merged.
+
+			// Eliminate at once
+			ptr->data.second %= k;
+
+			// Check if totally removed
+			if (ptr->data.second) {
+				ptr = ptr->next;
+				continue;
+			}
+
+			// Totally removed!
+			// possible to be merged
+			ptr = cnt.erase(ptr);
+			if (cnt.empty())
+				break;
+			if (ptr != cnt.begin())
+				ptr = ptr->prev;
+			auto prevPtr = ptr;
+			ptr = ptr->next;
+			while (ptr != cnt.end() && prevPtr->data.first == ptr->data.first) {
+				prevPtr->data.second += ptr->data.second;
+				ptr = cnt.erase(ptr);
+			}
+
+			ptr = prevPtr;
+		}
+
+		std::string ret;
+		for (auto* ptr = cnt.begin(); ptr != cnt.end(); ptr = ptr->next) {
+			const auto [ch, n] = ptr->data;
+			ret.append(n, ch);
+		}
+		return ret;
+	}
+};
+
+class Stopwatch {
+private:
+	std::chrono::high_resolution_clock::time_point start;
+public:
+	Stopwatch() {
+		this->start = std::chrono::high_resolution_clock::now();
+	}
+
+	~Stopwatch() {
+		std::printf("Time elapsed: %.6lf ms\n", std::chrono::duration_cast<std::chrono::nanoseconds>(std::chrono::high_resolution_clock::now() - start).count() / 1000000.0);
+	}
+};
+
+int main() {
+	std::string arg;
+	arg.reserve(100000);
+	for (int i = 0; i < 1923; ++i)
+		arg += "abcdefghijklmnopqrstuvwxyz";
+	for (int i = 0; i < 1923; ++i)
+		arg += "zyxwvutsrqponmlkjihgfedcba";
+	{
+		Stopwatch s;
+		std::cout << Solution::removeDuplicates(arg, 2) << "\n";
+	}
+	return 0;
+}

cpp/2205/CMakeLists.txt

@@ -3,4 +3,4 @@ PROJECT(2205)
 
 SET(CMAKE_CXX_STANDARD 23)
 
-ADD_EXECUTABLE(2204 220505.cpp)
+ADD_EXECUTABLE(2205 220506.cpp)