add: 220331 [cpp]
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#include <vector>
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#include <iostream>
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/**
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* 410. Split Array Largest Sum
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* Given an array nums which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays.
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* Write an algorithm to minimize the largest sum among these m subarrays.
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*/
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class Solution {
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private:
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// dp[remaining][startPoint]
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int dp[51][1002]{};
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int prefixSum[1002]{};
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int n = -1;
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const std::vector<int>* num = nullptr;
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// [remaining] segments to split,
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// from [startPoint] (inclusive) to the end.
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int d(int remaining, int startPoint) {
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if (dp[remaining][startPoint])
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return dp[remaining][startPoint];
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if (remaining <= 1)
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return dp[1][startPoint] = prefixSum[n - 1] - (startPoint ? prefixSum[startPoint - 1] : 0);
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// We should make sure that we will never
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// let remaining < n - startPoint.
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// nextRemaining <- remaining - 1;
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// from startPoint + 1, while i + nextRemaining < n;
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int currentSum = num->at(startPoint), ret = 0x7FFFFFFF;
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for (int i = 1 + startPoint; i + remaining - 1 <= n; ++i) {
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ret = std::min(ret, std::max(currentSum, d(remaining - 1, i)));
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currentSum += num->at(i);
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}
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return dp[remaining][startPoint] = ret;
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}
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public:
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int splitArray(const std::vector<int>& nums, int m) {
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std::vector<int> processed;
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processed.reserve(nums.size() / 2);
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for (int i : nums)
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if (i)
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processed.push_back(i);
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n = processed.size();
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if (!n)
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return 0;
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num = &processed;
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m = std::min(m, n);
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prefixSum[0] = processed[0];
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for (int i = 1; i < n; ++i)
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prefixSum[i] = prefixSum[i - 1] + processed[i];
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return d(m, 0);
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}
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};
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int main() {
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Solution s;
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std::cout << s.splitArray({7,2,5,10,8}, 2);
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// std::cout << s.splitArray({1,2,3,4,5}, 2);
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// std::cout << s.splitArray({1,4,4}, 3);
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return 0;
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}
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@ -3,4 +3,4 @@ PROJECT(2203)
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SET(CMAKE_CXX_STANDARD 23)
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SET(CMAKE_CXX_STANDARD 23)
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ADD_EXECUTABLE(2203 220331-CN.cpp)
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ADD_EXECUTABLE(2203 220331.cpp)
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